- #1

- 4

- 0

## Homework Statement

"Find the area of a parallelogram defined by the two vectors P=(4,-10,3) and Q=(2,1,0)"

## Homework Equations

The area of the parallelogram is equal to the magnitude of the cross product of the two vectors? i.e. Area = |PXQ|

## The Attempt at a Solution

PXQ = (-10x0-3x1)-(4x0-3x2)-(4x1-(-10)x2)=-3-(-6)-(-16)=25

-> area of parallelogram = 25(?)